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4y-3/y^2+1=4/y
We move all terms to the left:
4y-3/y^2+1-(4/y)=0
Domain of the equation: y^2!=0
y^2!=0/
y^2!=√0
y!=0
y∈R
Domain of the equation: y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
4y-3/y^2-(+4/y)+1=0
We get rid of parentheses
4y-3/y^2-4/y+1=0
We calculate fractions
We do not support eypression: y^3
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